Question 2
Assume we use 8 bits to store numbers.
a) 43 in unsigned binary
43 0010 1011
21 1
10 1
5 0
2 1
1 0
0 1
b) -43 in signed magnitude
1010 1011 sign bit = 1
c) -43 in 1's complement
1101 0100 complement bits
d) -43 in 2's complement
1101 0101 add 1
e) -43  in excess/bias
bias = 27 = 128
 -43 + 128 = 85 0101 0101 85 in base 2
f)  43  in BCD (Binary Coded Decimal)
0100 0011