(** * Hoare2: Hoare Logic, Part II *) Set Warnings "-notation-overridden,-parsing,-deprecated-hint-without-locality". From Coq Require Import Strings.String. From PLF Require Import Maps. From Coq Require Import Bool.Bool. From Coq Require Import Arith.Arith. From Coq Require Import Arith.EqNat. From Coq Require Import Arith.PeanoNat. Import Nat. From Coq Require Import Lia. From PLF Require Export Imp. From PLF Require Import Hoare. Definition FILL_IN_HERE := <{True}>. (* ################################################################# *) (** * Decorated Programs *) (** The beauty of Hoare Logic is that it is _structure-guided_: the structure of proofs exactly follows the structure of programs. We can record the essential ideas of a Hoare-logic proof -- omitting low-level calculational details -- by "decorating" a program with appropriate assertions on each of its commands. Such a _decorated program_ carries within itself an argument for its own correctness. *) (** For example, consider the program: X := m; Z := p; while X <> 0 do Z := Z - 1; X := X - 1 end *) (** Here is one possible specification for this program, in the form of a Hoare triple: {{ True }} X := m; Z := p; while X <> 0 do Z := Z - 1; X := X - 1 end {{ Z = p - m }} *) (** (Note the _parameters_ [m] and [p], which stand for fixed-but-arbitrary numbers. Formally, they are simply Coq variables of type [nat].) *) (** Here is a decorated version of this program, embodying a proof of this specification: {{ True }} ->> {{ m = m }} X := m {{ X = m }} ->> {{ X = m /\ p = p }}; Z := p; {{ X = m /\ Z = p }} ->> {{ Z - X = p - m }} while X <> 0 do {{ Z - X = p - m /\ X <> 0 }} ->> {{ (Z - 1) - (X - 1) = p - m }} Z := Z - 1 {{ Z - (X - 1) = p - m }}; X := X - 1 {{ Z - X = p - m }} end {{ Z - X = p - m /\ ~ (X <> 0) }} ->> {{ Z = p - m }} *) (** Concretely, a decorated program consists of the program's text interleaved with assertions (sometimes multiple assertions separated by implications). *) (** A decorated program can be viewed as a compact representation of a proof in Hoare Logic: the assertions surrounding each command specify the Hoare triple to be proved for that part of the program using one of the Hoare Logic rules, and the structure of the program itself shows how to assemble all these individual steps into a proof for the whole program. *) (** Our goal is to verify such decorated programs "mostly automatically." But, before we can verify anything, we need to be able to _find_ a proof for a given specification, and for this we need to discover the right assertions. This can be done in an almost mechanical way, with the exception of finding loop invariants. In the remainder of this section we explain in detail how to construct decorations for several short programs, all of which are loop-free or have simple loop invariants. We'll return finding more interesting loop invariants later in the chapter. *) (* ================================================================= *) (** ** Example: Swapping *) (** Consider the following program, which swaps the values of two variables using addition and subtraction (instead of by assigning to a temporary variable). X := X + Y; Y := X - Y; X := X - Y We can give a proof, in the form of decorations, that this program is correct -- i.e., it really swaps [X] and [Y] -- as follows. (1) {{ X = m /\ Y = n }} ->> (2) {{ (X + Y) - ((X + Y) - Y) = n /\ (X + Y) - Y = m }} X := X + Y (3) {{ X - (X - Y) = n /\ X - Y = m }}; Y := X - Y (4) {{ X - Y = n /\ Y = m }}; X := X - Y (5) {{ X = n /\ Y = m }} The decorations can be constructed as follows: - We begin with the undecorated program (the unnumbered lines). - We add the specification -- i.e., the outer precondition (1) and postcondition (5). In the precondition, we use parameters [m] and [n] to remember the initial values of variables [X] and [Y] so that we can refer to them in the postcondition (5). - We work backwards, mechanically, starting from (5) and proceeding until we get to (2). At each step, we obtain the precondition of the assignment from its postcondition by substituting the assigned variable with the right-hand-side of the assignment. For instance, we obtain (4) by substituting [X] with [X - Y] in (5), and we obtain (3) by substituting [Y] with [X - Y] in (4). Finally, we verify that (1) logically implies (2) -- i.e., that the step from (1) to (2) is a valid use of the law of consequence -- by doing a bit of high-school algebra. *) (* ================================================================= *) (** ** Example: Simple Conditionals *) (** Here is a simple decorated program using conditionals: (1) {{ True }} if X <= Y then (2) {{ True /\ X <= Y }} ->> (3) {{ (Y - X) + X = Y \/ (Y - X) + Y = X }} Z := Y - X (4) {{ Z + X = Y \/ Z + Y = X }} else (5) {{ True /\ ~(X <= Y) }} ->> (6) {{ (X - Y) + X = Y \/ (X - Y) + Y = X }} Z := X - Y (7) {{ Z + X = Y \/ Z + Y = X }} end (8) {{ Z + X = Y \/ Z + Y = X }} These decorations can be constructed as follows: - We start with the outer precondition (1) and postcondition (8). - Following the format dictated by the [hoare_if] rule, we copy the postcondition (8) to (4) and (7). We conjoin the precondition (1) with the guard of the conditional to obtain (2). We conjoin (1) with the negated guard of the conditional to obtain (5). - In order to use the assignment rule and obtain (3), we substitute [Z] by [Y - X] in (4). To obtain (6) we substitute [Z] by [X - Y] in (7). - Finally, we verify that (2) implies (3) and (5) implies (6). Both of these implications crucially depend on the ordering of [X] and [Y] obtained from the guard. For instance, knowing that [X <= Y] ensures that subtracting [X] from [Y] and then adding back [X] produces [Y], as required by the first disjunct of (3). Similarly, knowing that [~ (X <= Y)] ensures that subtracting [Y] from [X] and then adding back [Y] produces [X], as needed by the second disjunct of (6). Note that [n - m + m = n] does _not_ hold for arbitrary natural numbers [n] and [m] (for example, [3 - 5 + 5 = 5]). *) (** **** Exercise: 2 stars, standard, optional (if_minus_plus_reloaded) N.b.: Although this exercise is marked optional, it is an excellent warm-up for the (non-optional) [if_minus_plus_correct] exercise below! Fill in valid decorations for the following program: *) (* {{ True }} if X <= Y then {{ }} ->> {{ }} Z := Y - X {{ }} else {{ }} ->> {{ }} Y := X + Z {{ }} end {{ Y = X + Z }} *) (** Briefly justify each use of [->>]. *) (** [] *) (* ================================================================= *) (** ** Example: Reduce to Zero *) (** Here is a [while] loop that is so simple that [True] suffices as a loop invariant. (1) {{ True }} while X <> 0 do (2) {{ True /\ X <> 0 }} ->> (3) {{ True }} X := X - 1 (4) {{ True }} end (5) {{ True /\ ~(X <> 0) }} ->> (6) {{ X = 0 }} The decorations can be constructed as follows: - Start with the outer precondition (1) and postcondition (6). - Following the format dictated by the [hoare_while] rule, we copy (1) to (4). We conjoin (1) with the guard to obtain (2). We also conjoin (1) with the negation of the guard to obtain (5). - Because the final postcondition (6) does not syntactically match (5), we add an implication between them. - Using the assignment rule with assertion (4), we trivially substitute and obtain assertion (3). - We add the implication between (2) and (3). Finally we check that the implications do hold; both are trivial. *) (* ================================================================= *) (** ** Example: Division *) (** Let's do one more example of simple reasoning about a loop. The following Imp program calculates the integer quotient and remainder of parameters [m] and [n]. X := m; Y := 0; while n <= X do X := X - n; Y := Y + 1 end; If we replace [m] and [n] by concrete numbers and execute the program, it will terminate with the variable [X] set to the remainder when [m] is divided by [n] and [Y] set to the quotient. *) (** In order to give a specification to this program we need to remember that dividing [m] by [n] produces a remainder [X] and a quotient [Y] such that [n * Y + X = m /\ X < n]. It turns out that we get lucky with this program and don't have to think very hard about the loop invariant: the invariant is just the first conjunct, [n * Y + X = m], and we can use this to decorate the program. (1) {{ True }} ->> (2) {{ n * 0 + m = m }} X := m; (3) {{ n * 0 + X = m }} Y := 0; (4) {{ n * Y + X = m }} while n <= X do (5) {{ n * Y + X = m /\ n <= X }} ->> (6) {{ n * (Y + 1) + (X - n) = m }} X := X - n; (7) {{ n * (Y + 1) + X = m }} Y := Y + 1 (8) {{ n * Y + X = m }} end (9) {{ n * Y + X = m /\ ~ (n <= X) }} ->> (10) {{ n * Y + X = m /\ X < n }} Assertions (4), (5), (8), and (9) are derived mechanically from the invariant and the loop's guard. Assertions (8), (7), and (6) are derived using the assignment rule going backwards from (8) to (6). Assertions (4), (3), and (2) are again backwards applications of the assignment rule. Now that we've decorated the program it only remains to check that the uses of the consequence rule are correct -- i.e., that (1) implies (2), that (5) implies (6), and that (9) implies (10). This is indeed the case: - (1) ->> (2): trivial, by algebra. - (5) ->> (6): because [n <= X], we are guaranteed that the subtraction in (6) does not get zero-truncated. We can therefore rewrite (6) as [n * Y + n + X - n] and cancel the [n]s, which results in the left conjunct of (5). - (9) ->> (10): if [~ (n <= X)] then [X < n]. That's straightforward from high-school algebra. So, we have a valid decorated program. *) (* ================================================================= *) (** ** From Decorated Programs to Formal Proofs *) (** From an informal proof in the form of a decorated program, it is easy to read off a formal proof using the Coq theorems corresponding to the Hoare Logic rules. *) (** Note that we do _not_ unfold the definition of [hoare_triple] anywhere in this proof: the point of the game is to use the Hoare rules as a self-contained logic for reasoning about programs. *) (** For example... *) Definition reduce_to_zero' : com := <{ while X <> 0 do X := X - 1 end }>. Theorem reduce_to_zero_correct' : {{True}} reduce_to_zero' {{X = 0}}. Proof. unfold reduce_to_zero'. (* First we need to transform the postcondition so that hoare_while will apply. *) eapply hoare_consequence_post. - apply hoare_while. + (* Loop body preserves invariant *) (* Massage precondition so [hoare_asgn] applies *) eapply hoare_consequence_pre. * apply hoare_asgn. * (* Proving trivial implication (2) ->> (3) *) unfold assn_sub, "->>". simpl. intros. exact I. - (* Invariant and negated guard imply post *) intros st [Inv GuardFalse]. unfold bassn in GuardFalse. simpl in GuardFalse. rewrite not_true_iff_false in GuardFalse. rewrite negb_false_iff in GuardFalse. apply eqb_eq in GuardFalse. apply GuardFalse. Qed. (** In [Hoare] we introduced a series of tactics named [assn_auto] to automate proofs involving assertions. The following declaration introduces a more sophisticated tactic that will help with proving assertions throughout the rest of this chapter. You don't need to understand the details, but briefly: it uses [split] repeatedly to turn all the conjunctions into separate subgoals, tries to use several theorems about booleans and (in)equalities, then uses [eauto] and [lia] to finish off as many subgoals as possible. What's left after [verify_assn] does its thing should be just the "interesting parts" of the proof -- which, if we're lucky, might be nothing at all! *) Ltac verify_assn := repeat split; simpl; unfold assert_implies; unfold ap in *; unfold ap2 in *; unfold bassn in *; unfold beval in *; unfold aeval in *; unfold assn_sub; intros; repeat (simpl in *; rewrite t_update_eq || (try rewrite t_update_neq; [| (intro X; inversion X; fail)])); simpl in *; repeat match goal with [H : _ /\ _ |- _] => destruct H end; repeat rewrite not_true_iff_false in *; repeat rewrite not_false_iff_true in *; repeat rewrite negb_true_iff in *; repeat rewrite negb_false_iff in *; repeat rewrite eqb_eq in *; repeat rewrite eqb_neq in *; repeat rewrite leb_iff in *; repeat rewrite leb_iff_conv in *; try subst; simpl in *; repeat match goal with [st : state |- _] => match goal with | [H : st _ = _ |- _] => rewrite -> H in *; clear H | [H : _ = st _ |- _] => rewrite <- H in *; clear H end end; try eauto; try lia. (** This makes it pretty easy to verify [reduce_to_zero']: *) Theorem reduce_to_zero_correct''' : {{True}} reduce_to_zero' {{X = 0}}. Proof. unfold reduce_to_zero'. eapply hoare_consequence_post. - apply hoare_while. + eapply hoare_consequence_pre. * apply hoare_asgn. * verify_assn. - verify_assn. Qed. (** This example shows that it is conceptually straightforward to read off the main elements of a formal proof from a decorated program. Indeed, the process is so straightforward that it can be automated, as we show next. *) (* ################################################################# *) (** * Formal Decorated Programs *) (** Our informal conventions for decorated programs amount to a way of "displaying" Hoare triples, in which commands are annotated with enough embedded assertions that checking the validity of a triple is reduced to simple logical and algebraic calculations showing that some assertions imply others. In this section, we show that this presentation style can be made completely formal -- and indeed that checking the validity of decorated programs can be largely automated. *) (* ================================================================= *) (** ** Syntax *) (** The first thing we need to do is to formalize a variant of the syntax of commands that includes embedded assertions -- decorations. We call the new commands _decorated commands_, or [dcom]s. The choice of exactly where to put assertions in the definition of [dcom] is a bit subtle. The simplest thing to do would be to annotate every [dcom] with a precondition and postcondition. But this would result in very verbose decorated programs with a lot of repeated annotations: for example, a program like [skip;skip] would be decorated like this {{P}} ({{P}} skip {{P}}) ; ({{P}} skip {{P}}) {{P}} with pre- and post-conditions around each [skip], plus identical pre- and post-conditions on the semicolon! In other words, we don't want both preconditions and postconditions on each command, because a sequence of two commands would contain redundant decorations--the postcondition of the first likely being the same as the precondition of the second. Instead, the formal syntax of decorated commands omits preconditions whenever possible, trying to embed just the postcondition. *) (** Concretely, we decorate programs as follows... *) (** - The [skip] command is decorated only with its postcondition skip {{ Q }} on the assumption that the precondition will be provided by the context. We carry the same assumption through the other syntactic forms: each decorated command is assumed to carry its own postcondition within itself but take its precondition from its context in which it is used. *) (** - Sequences [d1 ; d2] need no additional decorations. Why? Inside [d2] there will be a postcondition; this serves as the postcondition of [d1;d2]. Inside [d1] there will also be a postcondition, which additionally serves as the precondition for [d2]. *) (** - An assignment [X := a] is decorated only with its postcondition: X := a {{ Q }} *) (** - A conditional [if b then d1 else d2] is decorated with a postcondition for the entire statement, as well as preconditions for each branch: if b then {{ P1 }} d1 else {{ P2 }} d2 end {{ Q }} *) (** - A loop [while b do d end] is decorated with its postcondition and a precondition for the body: while b do {{ P }} d end {{ Q }} The postcondition embedded in [d] serves as the loop invariant. *) (** - Implications [->>] can be added as decorations either for a precondition ->> {{ P }} d or for a postcondition d ->> {{ Q }} The former is waiting for another precondition to eventually be supplied (e.g., [{{ P'}} ->> {{ P }} d]); the latter relies on the postcondition already embedded in [d]. *) (** Here's the formal syntax of decorated commands: *) Inductive dcom : Type := | DCSkip (Q : Assertion) (* skip {{ Q }} *) | DCSeq (d1 d2 : dcom) (* d1 ; d2 *) | DCAsgn (X : string) (a : aexp) (Q : Assertion) (* X := a {{ Q }} *) | DCIf (b : bexp) (P1 : Assertion) (d1 : dcom) (P2 : Assertion) (d2 : dcom) (Q : Assertion) (* if b then {{ P1 }} d1 else {{ P2 }} d2 end {{ Q }} *) | DCWhile (b : bexp) (P : Assertion) (d : dcom) (Q : Assertion) (* while b do {{ P }} d end {{ Q }} *) | DCPre (P : Assertion) (d : dcom) (* ->> {{ P }} d *) | DCPost (d : dcom) (Q : Assertion) (* d ->> {{ Q }} *). (** To provide the initial precondition that goes at the very top of a decorated program, we introduce a new type [decorated]: *) Inductive decorated : Type := | Decorated : Assertion -> dcom -> decorated. (** To avoid clashing with the existing [Notation]s for ordinary [com]mands, we introduce these notations in a new grammar scope called [dcom]. *) Declare Scope dcom_scope. Notation "'skip' {{ P }}" := (DCSkip P) (in custom com at level 0, P constr) : dcom_scope. Notation "l ':=' a {{ P }}" := (DCAsgn l a P) (in custom com at level 0, l constr at level 0, a custom com at level 85, P constr, no associativity) : dcom_scope. Notation "'while' b 'do' {{ Pbody }} d 'end' {{ Ppost }}" := (DCWhile b Pbody d Ppost) (in custom com at level 89, b custom com at level 99, Pbody constr, Ppost constr) : dcom_scope. Notation "'if' b 'then' {{ P }} d 'else' {{ P' }} d' 'end' {{ Q }}" := (DCIf b P d P' d' Q) (in custom com at level 89, b custom com at level 99, P constr, P' constr, Q constr) : dcom_scope. Notation "'->>' {{ P }} d" := (DCPre P d) (in custom com at level 12, right associativity, P constr) : dcom_scope. Notation "d '->>' {{ P }}" := (DCPost d P) (in custom com at level 10, right associativity, P constr) : dcom_scope. Notation " d ; d' " := (DCSeq d d') (in custom com at level 90, right associativity) : dcom_scope. Notation "{{ P }} d" := (Decorated P d) (in custom com at level 91, P constr) : dcom_scope. Local Open Scope dcom_scope. Example dec0 := <{ skip {{ True }} }>. Example dec1 := <{ while true do {{ True }} skip {{ True }} end {{ True }} }>. (** Recall that you can [Set Printing All] to see how all that notation is desugared. *) Set Printing All. Print dec1. Unset Printing All. (** An example [decorated] program that decrements [X] to [0]: *) Example dec_while : decorated := <{ {{ True }} while X <> 0 do {{ True /\ (X <> 0) }} X := X - 1 {{ True }} end {{ True /\ X = 0}} ->> {{ X = 0 }} }>. (** It is easy to go from a [dcom] to a [com] by erasing all annotations. *) Fixpoint extract (d : dcom) : com := match d with | DCSkip _ => CSkip | DCSeq d1 d2 => CSeq (extract d1) (extract d2) | DCAsgn X a _ => CAsgn X a | DCIf b _ d1 _ d2 _ => CIf b (extract d1) (extract d2) | DCWhile b _ d _ => CWhile b (extract d) | DCPre _ d => extract d | DCPost d _ => extract d end. Definition extract_dec (dec : decorated) : com := match dec with | Decorated P d => extract d end. Example extract_while_ex : extract_dec dec_while = <{while X <> 0 do X := X - 1 end}>. Proof. unfold dec_while. reflexivity. Qed. (** It is also straightforward to extract the precondition and postcondition from a decorated program. *) Definition pre_dec (dec : decorated) : Assertion := match dec with | Decorated P d => P end. Fixpoint post (d : dcom) : Assertion := match d with | DCSkip P => P | DCSeq _ d2 => post d2 | DCAsgn _ _ Q => Q | DCIf _ _ _ _ _ Q => Q | DCWhile _ _ _ Q => Q | DCPre _ d => post d | DCPost _ Q => Q end. Definition post_dec (dec : decorated) : Assertion := match dec with | Decorated P d => post d end. Example pre_dec_while : pre_dec dec_while = True. Proof. reflexivity. Qed. Example post_dec_while : post_dec dec_while = (X = 0)%assertion. Proof. reflexivity. Qed. (** We can then express what it means for a decorated program to be correct as follows: *) Definition outer_triple_valid (dec : decorated) := {{pre_dec dec}} extract_dec dec {{post_dec dec}}. Example dec_while_triple_correct : outer_triple_valid dec_while = {{ True }} while X <> 0 do X := X - 1 end {{ X = 0 }}. Proof. reflexivity. Qed. (** Remember that the outer Hoare triple of a decorated program is just a [Prop]; thus, to show that it is _valid_, we need to produce a proof of this proposition. We will do this by extracting "proof obligations" from the decorations sprinkled through the program. These obligations are often called _verification conditions_, because they are the facts that must be verified to see that the decorations are locally consistent and thus constitute a proof of correctness. *) (* ================================================================= *) (** ** Extracting Verification Conditions *) (** The function [verification_conditions] takes a decorated command [d] together with a precondition [P] and returns a _proposition_ that, if it can be proved, implies that the triple {{P}} (extract d) {{post d}} is valid. It does this by walking over [d] and generating a big conjunction that includes - local consistency checks for each form of command, plus - uses of [->>] to bridge the gap between the assertions found inside a decorated command and the assertions imposed by its context; these uses correspond to applications of the consequence rule. *) (** - The decorated command skip {{Q}} is locally consistent with respect to a precondition [P] if [P ->> Q]. *) (** - The sequential composition of [d1] and [d2] is locally consistent with respect [P] if [d1] is locally consistent with respect to [P] and [d2] is locally consistent with respect to the postcondition of [d1]. *) (** - An assignment X := a {{Q}} is locally consistent with respect to a precondition [P] if: P ->> Q [X |-> a] *) (** - A conditional if b then {{P1}} d1 else {{P2}} d2 end is locally consistent with respect to precondition [P] if (1) [P /\ b ->> P1] (2) [P /\ ~b ->> P2] (3) [d1] is locally consistent with respect to [P1] (4) [d2] is locally consistent with respect to [P2] *) (** - A loop while b do {{Q}} d end {{R}} is locally consistent with respect to precondition [P] if: (1) [P ->> post d] (2) [post d /\ b ->> Q] (3) [post d /\ ~b ->> R] (4) [d] is locally consistent with respect to [Q] *) (** - A command with an extra assertion at the beginning --> {{Q}} d is locally consistent with respect to a precondition [P] if: (1) [P ->> Q] (1) [d] is locally consistent with respect to [Q] *) (** - A command with an extra assertion at the end d ->> {{Q}} is locally consistent with respect to a precondition [P] if: (1) [d] is locally consistent with respect to [P] (2) [post d ->> Q] *) Fixpoint verification_conditions (P : Assertion) (d : dcom) : Prop := match d with | DCSkip Q => (P ->> Q) | DCSeq d1 d2 => verification_conditions P d1 /\ verification_conditions (post d1) d2 | DCAsgn X a Q => (P ->> Q [X |-> a]) | DCIf b P1 d1 P2 d2 Q => ((P /\ b) ->> P1)%assertion /\ ((P /\ ~ b) ->> P2)%assertion /\ (post d1 ->> Q) /\ (post d2 ->> Q) /\ verification_conditions P1 d1 /\ verification_conditions P2 d2 | DCWhile b Pbody d Ppost => (* post d is the loop invariant and the initial precondition *) (P ->> post d) /\ ((post d /\ b) ->> Pbody)%assertion /\ ((post d /\ ~ b) ->> Ppost)%assertion /\ verification_conditions Pbody d | DCPre P' d => (P ->> P') /\ verification_conditions P' d | DCPost d Q => verification_conditions P d /\ (post d ->> Q) end. (** The key theorem states that [verification_conditions] does its job correctly. Not surprisingly, we need to use each of the Hoare Logic rules at some point in the proof. *) Theorem verification_correct : forall d P, verification_conditions P d -> {{P}} extract d {{post d}}. Proof. induction d; intros; simpl in *. - (* Skip *) eapply hoare_consequence_pre. + apply hoare_skip. + assumption. - (* Seq *) destruct H as [H1 H2]. eapply hoare_seq. + apply IHd2. apply H2. + apply IHd1. apply H1. - (* Asgn *) eapply hoare_consequence_pre. + apply hoare_asgn. + assumption. - (* If *) destruct H as [HPre1 [HPre2 [Hd1 [Hd2 [HThen HElse] ] ] ] ]. apply IHd1 in HThen. clear IHd1. apply IHd2 in HElse. clear IHd2. apply hoare_if. + eapply hoare_consequence; eauto. + eapply hoare_consequence; eauto. - (* While *) destruct H as [Hpre [Hbody1 [Hpost1 Hd] ] ]. eapply hoare_consequence; eauto. apply hoare_while. eapply hoare_consequence_pre; eauto. - (* Pre *) destruct H as [HP Hd]. eapply hoare_consequence_pre; eauto. - (* Post *) destruct H as [Hd HQ]. eapply hoare_consequence_post; eauto. Qed. (** Now that all the pieces are in place, we can define what it means to verify an entire program. *) Definition verification_conditions_dec (dec : decorated) : Prop := match dec with | Decorated P d => verification_conditions P d end. Corollary verification_correct_dec : forall dec, verification_conditions_dec dec -> outer_triple_valid dec. Proof. intros [P d]. apply verification_correct. Qed. (* ================================================================= *) (** ** Automation *) (** The propositions generated by [verification_conditions] are fairly big and contain many conjuncts that are essentially trivial. *) Eval simpl in verification_conditions_dec dec_while. (* ==> ((fun _ : state => True) ->> (fun _ : state => True)) /\ ((fun st : state => True /\ negb (st X =? 0) = true) ->> (fun st : state => True /\ st X <> 0)) /\ ((fun st : state => True /\ negb (st X =? 0) <> true) ->> (fun st : state => True /\ st X = 0)) /\ (fun st : state => True /\ st X <> 0) ->> (fun _ : state => True) [X |-> X - 1]) /\ (fun st : state => True /\ st X = 0) ->> (fun st : state => st X = 0) : Prop *) (** Fortunately, our [verify_assn] tactic can generally take care of most or all of them. *) Example vc_dec_while : verification_conditions_dec dec_while. Proof. verify_assn. Qed. (** To automate the overall process of verification, we can use [verification_correct] to extract the verification conditions, use [verify_assn] to verify them as much as it can, and finally tidy up any remaining bits by hand. *) Ltac verify := intros; apply verification_correct; verify_assn. (** Here's the final, formal proof that dec_while is correct. *) Theorem dec_while_correct : outer_triple_valid dec_while. Proof. verify. Qed. (** Similarly, here is the formal decorated program for the "swapping by adding and subtracting" example that we saw earlier. *) Definition swap_dec (m n:nat) : decorated := <{ {{ X = m /\ Y = n}} ->> {{ (X + Y) - ((X + Y) - Y) = n /\ (X + Y) - Y = m }} X := X + Y {{ X - (X - Y) = n /\ X - Y = m }}; Y := X - Y {{ X - Y = n /\ Y = m }}; X := X - Y {{ X = n /\ Y = m}} }>. Theorem swap_correct : forall m n, outer_triple_valid (swap_dec m n). Proof. verify. Qed. (** And here is the formal decorated version of the "positive difference" program from earlier: *) Definition positive_difference_dec := <{ {{True}} if X <= Y then {{True /\ X <= Y}} ->> {{(Y - X) + X = Y \/ (Y - X) + Y = X}} Z := Y - X {{Z + X = Y \/ Z + Y = X}} else {{True /\ ~(X <= Y)}} ->> {{(X - Y) + X = Y \/ (X - Y) + Y = X}} Z := X - Y {{Z + X = Y \/ Z + Y = X}} end {{Z + X = Y \/ Z + Y = X}} }>. Theorem positive_difference_correct : outer_triple_valid positive_difference_dec. Proof. verify. Qed. (** **** Exercise: 2 stars, standard, optional (if_minus_plus_correct) Here is a skeleton of the formal decorated version of the [if_minus_plus] program that we saw earlier. Replace all occurrences of [FILL_IN_HERE] with appropriate assertions and fill in the proof (which should be just as straightforward as in the examples above). *) Definition if_minus_plus_dec := <{ {{True}} if (X <= Y) then {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} Z := Y - X {{ FILL_IN_HERE }} else {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} Y := X + Z {{ FILL_IN_HERE }} end {{ Y = X + Z}} }>. Theorem if_minus_plus_correct : outer_triple_valid if_minus_plus_dec. Proof. (* FILL IN HERE *) Admitted. (** [] *) (** **** Exercise: 2 stars, standard, optional (div_mod_outer_triple_valid) Fill in appropriate assertions for the division program from above. *) Definition div_mod_dec (a b : nat) : decorated := <{ {{ True }} ->> {{ FILL_IN_HERE }} X := a {{ FILL_IN_HERE }}; Y := 0 {{ FILL_IN_HERE }}; while b <= X do {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} X := X - b {{ FILL_IN_HERE }}; Y := Y + 1 {{ FILL_IN_HERE }} end {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} }>. Theorem div_mod_outer_triple_valid : forall a b, outer_triple_valid (div_mod_dec a b). Proof. (* FILL IN HERE *) Admitted. (** [] *) (* ################################################################# *) (** * Finding Loop Invariants *) (** Once the outermost precondition and postcondition are chosen, the only creative part of a verifying program using Hoare Logic is finding the right loop invariants. The reason this is difficult is the same as the reason that inductive mathematical proofs are: - Strengthening a _loop invariant_ means that you have a stronger assumption to work with when trying to establish the postcondition of the loop body, but it also means that the loop body's postcondition is stronger and thus harder to prove. - Strengthening an _induction hypothesis_ means that you have a stronger assumption to work with when trying to complete the induction step of the proof, but it also means that the statement being proved inductively is stronger and thus harder to prove. This section explains how to approach the challenge of finding loop invariants through a series of examples and exercises. *) (* ================================================================= *) (** ** Example: Slow Subtraction *) (** The following program subtracts the value of [X] from the value of [Y] by repeatedly decrementing both [X] and [Y]. We want to verify its correctness with respect to the pre- and postconditions shown: {{ X = m /\ Y = n }} while X <> 0 do Y := Y - 1; X := X - 1 end {{ Y = n - m }} *) (** To verify this program, we need to find an invariant [Inv] for the loop. As a first step we can leave [Inv] as an unknown and build a _skeleton_ for the proof by applying the rules for local consistency, working from the end of the program to the beginning, as usual, and without any thinking at all yet. *) (** This leads to the following skeleton: (1) {{ X = m /\ Y = n }} ->> (a) (2) {{ Inv }} while X <> 0 do (3) {{ Inv /\ X <> 0 }} ->> (c) (4) {{ Inv [X |-> X-1] [Y |-> Y-1] }} Y := Y - 1; (5) {{ Inv [X |-> X-1] }} X := X - 1 (6) {{ Inv }} end (7) {{ Inv /\ ~ (X <> 0) }} ->> (b) (8) {{ Y = n - m }} *) (** By examining this skeleton, we can see that any valid [Inv] will have to respect three conditions: - (a) it must be _weak_ enough to be implied by the loop's precondition, i.e., (1) must imply (2); - (b) it must be _strong_ enough to imply the program's postcondition, i.e., (7) must imply (8); - (c) it must be _preserved_ by each iteration of the loop (given that the loop guard evaluates to true), i.e., (3) must imply (4). *) (** These conditions are actually independent of the particular program and specification we are considering: every loop invariant has to satisfy them. One way to find an invariant that simultaneously satisfies these three conditions is by using an iterative process: start with a "candidate" invariant (e.g., a guess or a heuristic choice) and check the three conditions above; if any of the checks fails, try to use the information that we get from the failure to produce another -- hopefully better -- candidate invariant, and repeat. For instance, in the reduce-to-zero example above, we saw that, for a very simple loop, choosing [True] as an invariant did the job. Maybe it will work here too. To find out, let's try instantiating [Inv] with [True] in the skeleton above and see what we get... (1) {{ X = m /\ Y = n }} ->> (a - OK) (2) {{ True }} while X <> 0 do (3) {{ True /\ X <> 0 }} ->> (c - OK) (4) {{ True }} Y := Y - 1; (5) {{ True }} X := X - 1 (6) {{ True }} end (7) {{ True /\ ~(X <> 0) }} ->> (b - WRONG!) (8) {{ Y = n - m }} While conditions (a) and (c) are trivially satisfied, (b) is wrong: it is not the case that [True /\ X = 0] (7) implies [Y = n - m] (8). In fact, the two assertions are completely unrelated, so it is very easy to find a counterexample to the implication (say, [Y = X = m = 0] and [n = 1]). If we want (b) to hold, we need to strengthen the invariant so that it implies the postcondition (8). One simple way to do this is to let the invariant _be_ the postcondition. So let's return to our skeleton, instantiate [Inv] with [Y = n - m], and try checking conditions (a) to (c) again. (1) {{ X = m /\ Y = n }} ->> (a - WRONG!) (2) {{ Y = n - m }} while X <> 0 do (3) {{ Y = n - m /\ X <> 0 }} ->> (c - WRONG!) (4) {{ Y - 1 = n - m }} Y := Y - 1; (5) {{ Y = n - m }} X := X - 1 (6) {{ Y = n - m }} end (7) {{ Y = n - m /\ ~(X <> 0) }} ->> (b - OK) (8) {{ Y = n - m }} This time, condition (b) holds trivially, but (a) and (c) are broken. Condition (a) requires that (1) [X = m /\ Y = n] implies (2) [Y = n - m]. If we substitute [Y] by [n] we have to show that [n = n - m] for arbitrary [m] and [n], which is not the case (for instance, when [m = n = 1]). Condition (c) requires that [n - m - 1 = n - m], which fails, for instance, for [n = 1] and [m = 0]. So, although [Y = n - m] holds at the end of the loop, it does not hold from the start, and it doesn't hold on each iteration; it is not a correct invariant. This failure is not very surprising: the variable [Y] changes during the loop, while [m] and [n] are constant, so the assertion we chose didn't have much chance of being an invariant! To do better, we need to generalize (8) to some statement that is equivalent to (8) when [X] is [0], since this will be the case when the loop terminates, and that "fills the gap" in some appropriate way when [X] is nonzero. Looking at how the loop works, we can observe that [X] and [Y] are decremented together until [X] reaches [0]. So, if [X = 2] and [Y = 5] initially, after one iteration of the loop we obtain [X = 1] and [Y = 4]; after two iterations [X = 0] and [Y = 3]; and then the loop stops. Notice that the difference between [Y] and [X] stays constant between iterations: initially, [Y = n] and [X = m], and the difference is always [n - m]. So let's try instantiating [Inv] in the skeleton above with [Y - X = n - m]. (1) {{ X = m /\ Y = n }} ->> (a - OK) (2) {{ Y - X = n - m }} while X <> 0 do (3) {{ Y - X = n - m /\ X <> 0 }} ->> (c - OK) (4) {{ (Y - 1) - (X - 1) = n - m }} Y := Y - 1; (5) {{ Y - (X - 1) = n - m }} X := X - 1 (6) {{ Y - X = n - m }} end (7) {{ Y - X = n - m /\ ~(X <> 0) }} ->> (b - OK) (8) {{ Y = n - m }} Success! Conditions (a), (b) and (c) all hold now. (To verify (c), we need to check that, under the assumption that [X <> 0], we have [Y - X = (Y - 1) - (X - 1)]; this holds for all natural numbers [X] and [Y].) Here is the final version of the decorated program: *) Example subtract_slowly_dec (m : nat) (p : nat) : decorated := <{ {{ X = m /\ Z = p }} ->> {{ Z - X = p - m }} while X <> 0 do {{ Z - X = p - m /\ X <> 0 }} ->> {{ (Z - 1) - (X - 1) = p - m }} Z := Z - 1 {{ Z - (X - 1) = p - m }} ; X := X - 1 {{ Z - X = p - m }} end {{ Z - X = p - m /\ X = 0 }} ->> {{ Z = p - m }} }>. Theorem subtract_slowly_outer_triple_valid : forall m p, outer_triple_valid (subtract_slowly_dec m p). Proof. (* FILL IN HERE *) Admitted. (* ================================================================= *) (** ** Exercise: Slow Assignment *) (** **** Exercise: 2 stars, standard, optional (slow_assignment) A roundabout way of assigning a number currently stored in [X] to the variable [Y] is to start [Y] at [0], then decrement [X] until it hits [0], incrementing [Y] at each step. Here is a program that implements this idea. Fill in decorations and prove the decorated program correct. (The proof should be very simple.) *) Example slow_assignment_dec (m : nat) : decorated := <{ {{ X = m }} Y := 0 {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} ; while X <> 0 do {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} X := X - 1 {{ FILL_IN_HERE }} ; Y := Y + 1 {{ FILL_IN_HERE }} end {{ FILL_IN_HERE }} ->> {{ Y = m }} }>. Theorem slow_assignment : forall m, outer_triple_valid (slow_assignment_dec m). Proof. (* FILL IN HERE *) Admitted. (** [] *) (* ================================================================= *) (** ** Example: Parity *) (** Here is a cute way of computing the parity of a value initially stored in [X], due to Daniel Cristofani. {{ X = m }} while 2 <= X do X := X - 2 end {{ X = parity m }} The [parity] function used in the specification is defined in Coq as follows: *) Fixpoint parity x := match x with | 0 => 0 | 1 => 1 | S (S x') => parity x' end. (** The postcondition does not hold at the beginning of the loop, since [m = parity m] does not hold for an arbitrary [m], so we cannot hope to use that as an invariant. To find an invariant that works, let's think a bit about what this loop does. On each iteration it decrements [X] by [2], which preserves the parity of [X]. So the parity of [X] does not change, i.e., it is invariant. The initial value of [X] is [m], so the parity of [X] is always equal to the parity of [m]. Using [parity X = parity m] as an invariant we obtain the following decorated program: {{ X = m }} ->> (a - OK) {{ parity X = parity m }} while 2 <= X do {{ parity X = parity m /\ 2 <= X }} ->> (c - OK) {{ parity (X-2) = parity m }} X := X - 2 {{ parity X = parity m }} end {{ parity X = parity m /\ ~(2 <= X) }} ->> (b - OK) {{ X = parity m }} With this invariant, conditions (a), (b), and (c) are all satisfied. For verifying (b), we observe that, when [X < 2], we have [parity X = X] (we can easily see this in the definition of [parity]). For verifying (c), we observe that, when [2 <= X], we have [parity X = parity (X-2)]. *) (** **** Exercise: 3 stars, standard, optional (parity_formal) Translate the above informal decorated program into a formal one and prove it correct. Hint: There are actually several possible loop invariants that all lead to good proofs; one that leads to a particularly simple proof is [parity X = parity m /\ 2 <= X] -- or more formally, using the [ap] operator to lift the application of the [parity] function into the syntax of assertions, [{{ ap parity X = parity m /\ 2 <= X }}]. *) Definition parity_dec (m:nat) : decorated := <{ {{ X = m }} ->> {{ FILL_IN_HERE }} while 2 <= X do {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} X := X - 2 {{ FILL_IN_HERE }} end {{ FILL_IN_HERE }} ->> {{ X = parity m }} }>. (** If you use the suggested invariant, you may find the following lemmas helpful (as well as [leb_complete] and [leb_correct]). *) Lemma parity_ge_2 : forall x, 2 <= x -> parity (x - 2) = parity x. Proof. induction x; intros; simpl. - reflexivity. - destruct x. + lia. + inversion H; subst; simpl. * reflexivity. * rewrite sub_0_r. reflexivity. Qed. Lemma parity_lt_2 : forall x, ~ 2 <= x -> parity x = x. Proof. induction x; intros; simpl. - reflexivity. - destruct x. + reflexivity. + lia. Qed. Theorem parity_outer_triple_valid : forall m, outer_triple_valid (parity_dec m). Proof. (* FILL IN HERE *) Admitted. (** [] *) (* ================================================================= *) (** ** Example: Finding Square Roots *) (** The following program computes the integer square root of [X] by naive iteration: {{ X=m }} Z := 0; while (Z+1)*(Z+1) <= X do Z := Z+1 end {{ Z*Z<=m /\ m<(Z+1)*(Z+1) }} *) (** As we did before, we can try to use the postcondition as a candidate invariant, obtaining the following decorated program: (1) {{ X=m }} ->> (a - second conjunct of (2) WRONG!) (2) {{ 0*0 <= m /\ m<(0+1)*(0+1) }} Z := 0 (3) {{ Z*Z <= m /\ m<(Z+1)*(Z+1) }}; while (Z+1)*(Z+1) <= X do (4) {{ Z*Z<=m /\ (Z+1)*(Z+1)<=X }} ->> (c - WRONG!) (5) {{ (Z+1)*(Z+1)<=m /\ m<((Z+1)+1)*((Z+1)+1) }} Z := Z+1 (6) {{ Z*Z<=m /\ m<(Z+1)*(Z+1) }} end (7) {{ Z*Z<=m /\ m<(Z+1)*(Z+1) /\ ~((Z+1)*(Z+1)<=X) }} ->> (b - OK) (8) {{ Z*Z<=m /\ m<(Z+1)*(Z+1) }} This didn't work very well: conditions (a) and (c) both failed. Looking at condition (c), we see that the second conjunct of (4) is almost the same as the first conjunct of (5), except that (4) mentions [X] while (5) mentions [m]. But note that [X] is never assigned in this program, so we should always have [X=m]. We didn't propagate this information from (1) into the loop invariant, but we could! Also, we don't need the second conjunct of (8), since we can obtain it from the negation of the guard -- the third conjunct in (7) -- again under the assumption that [X=m]. This allows us to simplify a bit. So we now try [X=m /\ Z*Z <= m] as the loop invariant: {{ X=m }} ->> (a - OK) {{ X=m /\ 0*0 <= m }} Z := 0 {{ X=m /\ Z*Z <= m }}; while (Z+1)*(Z+1) <= X do {{ X=m /\ Z*Z<=m /\ (Z+1)*(Z+1)<=X }} ->> (c - OK) {{ X=m /\ (Z+1)*(Z+1)<=m }} Z := Z + 1 {{ X=m /\ Z*Z<=m }} end {{ X=m /\ Z*Z<=m /\ ~((Z+1)*(Z+1)<=X) }} ->> (b - OK) {{ Z*Z<=m /\ m<(Z+1)*(Z+1) }} This works, since conditions (a), (b), and (c) are now all trivially satisfied. Very often, when a variable is used in a loop in a read-only fashion (i.e., it is referred to by the program or by the specification and it is not changed by the loop), it is necessary to record the fact that it doesn't change in the loop invariant. *) (** **** Exercise: 3 stars, standard, optional (sqrt_formal) Translate the above informal decorated program into a formal one and prove it correct. Hint: The loop invariant here must ensure that Z*Z is consistently less than or equal to X. *) Definition sqrt_dec (m:nat) : decorated := <{ {{ X = m }} ->> {{ FILL_IN_HERE }} Z := 0 {{ FILL_IN_HERE }}; while ((Z+1)*(Z+1) <= X) do {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} Z := Z + 1 {{ FILL_IN_HERE }} end {{ FILL_IN_HERE }} ->> {{ Z*Z<=m /\ m<(Z+1)*(Z+1) }} }>. Theorem sqrt_correct : forall m, outer_triple_valid (sqrt_dec m). Proof. (* FILL IN HERE *) Admitted. (* ================================================================= *) (** ** Example: Squaring *) (** Here is a program that squares [X] by repeated addition: {{ X = m }} Y := 0; Z := 0; while Y <> X do Z := Z + X; Y := Y + 1 end {{ Z = m*m }} *) (** The first thing to note is that the loop reads [X] but doesn't change its value. As we saw in the previous example, it can be a good idea in such cases to add [X = m] to the invariant. The other thing that we know is often useful in the invariant is the postcondition, so let's add that too, leading to the candidate invariant [Z = m * m /\ X = m]. {{ X = m }} ->> (a - WRONG) {{ 0 = m*m /\ X = m }} Y := 0 {{ 0 = m*m /\ X = m }}; Z := 0 {{ Z = m*m /\ X = m }}; while Y <> X do {{ Z = m*m /\ X = m /\ Y <> X }} ->> (c - WRONG) {{ Z+X = m*m /\ X = m }} Z := Z + X {{ Z = m*m /\ X = m }}; Y := Y + 1 {{ Z = m*m /\ X = m }} end {{ Z = m*m /\ X = m /\ ~(Y <> X) }} ->> (b - OK) {{ Z = m*m }} Conditions (a) and (c) fail because of the [Z = m*m] part. While [Z] starts at [0] and works itself up to [m*m], we can't expect [Z] to be [m*m] from the start. If we look at how [Z] progresses in the loop, after the 1st iteration [Z = m], after the 2nd iteration [Z = 2*m], and at the end [Z = m*m]. Since the variable [Y] tracks how many times we go through the loop, this leads us to derive a new invariant candidate: [Z = Y*m /\ X = m]. {{ X = m }} ->> (a - OK) {{ 0 = 0*m /\ X = m }} Y := 0; {{ 0 = Y*m /\ X = m }} Z := 0; {{ Z = Y*m /\ X = m }} while Y <> X do {{ Z = Y*m /\ X = m /\ Y <> X }} ->> (c - OK) {{ Z+X = (Y+1)*m /\ X = m }} Z := Z + X; {{ Z = (Y+1)*m /\ X = m }} Y := Y + 1 {{ Z = Y*m /\ X = m }} end {{ Z = Y*m /\ X = m /\ ~(Y <> X) }} ->> (b - OK) {{ Z = m*m }} This new invariant makes the proof go through: all three conditions are easy to check. It is worth comparing the postcondition [Z = m*m] and the [Z = Y*m] conjunct of the invariant. It is often the case that one has to replace parameters with variables -- or with expressions involving both variables and parameters, like [m - Y] -- when going from postconditions to invariants. *) (** [] *) (* ================================================================= *) (** ** Exercise: Factorial *) (** **** Exercise: 4 stars, advanced, optional (factorial_correct) Recall that [n!] denotes the factorial of [n] (i.e., [n! = 1*2*...*n]). Formally, the factorial function is defined recursively in the Coq standard library in a way that is equivalent to the following: Fixpoint fact (n : nat) : nat := match n with | O => 1 | S n' => n * (fact n') end. *) Compute fact 5. (* ==> 120 *) (** First, write the Imp program [factorial] that calculates the factorial of the number initially stored in the variable [X] and puts it in the variable [Y]. *) (** Using your definition [factorial] and [slow_assignment_dec] as a guide, write a formal decorated program [factorial_dec] that implements the factorial function. Hint: recall the use of [ap] in assertions to apply a function to an Imp variable. Fill in the blanks and finish the proof of correctness. Bear in mind that we are working with natural numbers, for which both division and subtraction can behave differently than with real numbers. Excluding both operations from your loop invariant is advisable! Then state a theorem named [factorial_outer_triple_valid] that says [factorial_dec] is correct, and prove the theorem. If all goes well, [verify] will leave you with just two subgoals, each of which requires establishing some mathematical property of [fact], rather than proving anything about your program. Hint: if those two subgoals become tedious to prove, give some though to how you could restate your assertions such that the mathematical operations are more amenable to manipulation in Coq. For example, recall that [1 + ...] is easier to work with than [... + 1]. *) Example factorial_dec (m:nat) : decorated (* REPLACE THIS LINE WITH ":= _your_definition_ ." *). Admitted. (* FILL IN HERE *) Theorem factorial_correct: forall m, outer_triple_valid (factorial_dec m). Proof. (* FILL IN HERE *) Admitted. (** [] *) (* ================================================================= *) (** ** Exercise: Minimum *) (** **** Exercise: 3 stars, standard, optional (minimum_correct) Fill in decorations for the following program and prove them correct. As with [factorial], be careful about natural numbers, especially subtraction. Also, remember that applications of Coq functions in assertions need an [ap] or [ap2] to be parsed correctly. E.g., [min a b] needs to be written [ap2 min a b] in an assertion. Hint: You may find [andb_true_eq] useful (perhaps after using symmetry to get an equality the right way around). *) Definition minimum_dec (a b : nat) : decorated := <{ {{ True }} ->> {{ FILL_IN_HERE }} X := a {{ FILL_IN_HERE }}; Y := b {{ FILL_IN_HERE }}; Z := 0 {{ FILL_IN_HERE }}; while X <> 0 && Y <> 0 do {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} X := X - 1 {{ FILL_IN_HERE }}; Y := Y - 1 {{ FILL_IN_HERE }}; Z := Z + 1 {{ FILL_IN_HERE }} end {{ FILL_IN_HERE }} ->> {{ Z = min a b }} }>. Theorem minimum_correct : forall a b, outer_triple_valid (minimum_dec a b). Proof. (* FILL IN HERE *) Admitted. (** [] *) (* ================================================================= *) (** ** Exercise: Two Loops *) (** **** Exercise: 3 stars, standard (two_loops) Here is a pretty inefficient way of adding 3 numbers: {{ True }} X := 0; Y := 0; Z := c; while X <> a do X := X + 1; Z := Z + 1 end; while Y <> b do Y := Y + 1; Z := Z + 1 end {{ Z = a + b + c }} Show that it does what it should by completing the decoration of the program above. You can ignore the formal aspect of the exercise, or try to complete it to ensure the correctness of your decoration. *) Definition two_loops_dec (a b c : nat) : decorated := <{ {{ True }} ->> {{ FILL_IN_HERE }} X := 0 {{ FILL_IN_HERE }}; Y := 0 {{ FILL_IN_HERE }}; Z := c {{ FILL_IN_HERE }}; while X <> a do {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} X := X + 1 {{ FILL_IN_HERE }}; Z := Z + 1 {{ FILL_IN_HERE }} end {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }}; while Y <> b do {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} Y := Y + 1 {{ FILL_IN_HERE }}; Z := Z + 1 {{ FILL_IN_HERE }} end {{ FILL_IN_HERE }} ->> {{ Z = a + b + c }} }>. Theorem two_loops : forall a b c, outer_triple_valid (two_loops_dec a b c). Proof. (* FILL IN HERE *) Admitted. (** [] *) (* ================================================================= *) (** ** Exercise: Power Series *) (** **** Exercise: 4 stars, standard, optional (dpow2) Here is a program that computes the series: [1 + 2 + 2^2 + ... + 2^m = 2^(m+1) - 1] X := 0; Y := 1; Z := 1; while X <> m do Z := 2 * Z; Y := Y + Z; X := X + 1 end Turn this into a decorated program and prove it correct. *) Fixpoint pow2 n := match n with | 0 => 1 | S n' => 2 * (pow2 n') end. Definition dpow2_dec (n : nat) := <{ {{ True }} ->> {{ FILL_IN_HERE }} X := 0 {{ FILL_IN_HERE }}; Y := 1 {{ FILL_IN_HERE }}; Z := 1 {{ FILL_IN_HERE }}; while X <> n do {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} Z := 2 * Z {{ FILL_IN_HERE }}; Y := Y + Z {{ FILL_IN_HERE }}; X := X + 1 {{ FILL_IN_HERE }} end {{ FILL_IN_HERE }} ->> {{ Y = pow2 (n+1) - 1 }} }>. (** Some lemmas that you may find useful... *) Lemma pow2_plus_1 : forall n, pow2 (n+1) = pow2 n + pow2 n. Proof. induction n; simpl. reflexivity. lia. Qed. Lemma pow2_le_1 : forall n, pow2 n >= 1. Proof. induction n. simpl. constructor. simpl. lia. Qed. (** The main correctness theorem: *) Theorem dpow2_down_correct : forall n, outer_triple_valid (dpow2_dec n). Proof. (* FILL IN HERE *) Admitted. (** [] *) (* ################################################################# *) (** * Weakest Preconditions (Optional) *) (** Some preconditions are more interesting than others. For example, the Hoare triple {{ False }} X := Y + 1 {{ X <= 5 }} is _not_ very interesting: although it is perfectly valid , it tells us nothing useful. Since the precondition isn't satisfied by any state, it doesn't describe any situations where we can use the command [X := Y + 1] to achieve the postcondition [X <= 5]. By contrast, {{ Y <= 4 /\ Z = 0 }} X := Y + 1 {{ X <= 5 }} has a useful precondition: it tells us that, if we can somehow create a situation in which we know that [Y <= 4 /\ Z = 0], then running this command will produce a state satisfying the postcondition. However, this precondition is not as useful as it could be, because the [Z = 0] clause in the precondition actually has nothing to do with the postcondition [X <= 5]. The _most_ useful precondition for this command is this one: {{ Y <= 4 }} X := Y + 1 {{ X <= 5 }} The assertion [Y <= 4] is called the _weakest precondition_ of [X := Y + 1] with respect to the postcondition [X <= 5]. *) (** Assertion [Y <= 4] is a _weakest precondition_ of command [X := Y + 1] with respect to postcondition [X <= 5]. Think of _weakest_ here as meaning "easiest to satisfy": a weakest precondition is one that as many states as possible can satisfy. *) (** [P] is a weakest precondition of command [c] for postcondition [Q] if - [P] is a precondition, that is, [{{P}} c {{Q}}]; and - [P] is at least as weak as all other preconditions, that is, if [{{P'}} c {{Q}}] then [P' ->> P]. *) (** Note that weakest preconditions need not be unique. For example, [Y <= 4] was a weakest precondition above, but so are the logically equivalent assertions [Y < 5], [Y <= 2 * 2], etc. *) Definition is_wp P c Q := {{P}} c {{Q}} /\ forall P', {{P'}} c {{Q}} -> (P' ->> P). (** **** Exercise: 1 star, standard, optional (wp) What are weakest preconditions of the following commands for the following postconditions? 1) {{ ? }} skip {{ X = 5 }} 2) {{ ? }} X := Y + Z {{ X = 5 }} 3) {{ ? }} X := Y {{ X = Y }} 4) {{ ? }} if X = 0 then Y := Z + 1 else Y := W + 2 end {{ Y = 5 }} 5) {{ ? }} X := 5 {{ X = 0 }} 6) {{ ? }} while true do X := 0 end {{ X = 0 }} *) (* FILL IN HERE [] *) (** **** Exercise: 3 stars, advanced, optional (is_wp_formal) Prove formally, using the definition of [hoare_triple], that [Y <= 4] is indeed a weakest precondition of [X := Y + 1] with respect to postcondition [X <= 5]. *) Theorem is_wp_example : is_wp (Y <= 4) <{X := Y + 1}> (X <= 5). Proof. (* FILL IN HERE *) Admitted. (** [] *) (** **** Exercise: 2 stars, advanced, optional (hoare_asgn_weakest) Show that the precondition in the rule [hoare_asgn] is in fact the weakest precondition. *) Theorem hoare_asgn_weakest : forall Q X a, is_wp (Q [X |-> a]) <{ X := a }> Q. Proof. (* FILL IN HERE *) Admitted. (** [] *) (** **** Exercise: 2 stars, advanced, optional (hoare_havoc_weakest) Show that your [havoc_pre] function from the [himp_hoare] exercise in the [Hoare] chapter returns a weakest precondition. *) Module Himp2. Import Himp. Lemma hoare_havoc_weakest : forall (P Q : Assertion) (X : string), {{ P }} havoc X {{ Q }} -> P ->> havoc_pre X Q. Proof. (* FILL IN HERE *) Admitted. End Himp2. (** [] *) (** **** Exercise: 2 stars, advanced, optional (fib_eqn) The Fibonacci function is usually written like this: Fixpoint fib n := match n with | 0 => 1 | 1 => 1 | _ => fib (pred n) + fib (pred (pred n)) end. This doesn't pass Coq's termination checker, but here is a slightly clunkier definition that does: *) Fixpoint fib n := match n with | 0 => 1 | S n' => match n' with | 0 => 1 | S n'' => fib n' + fib n'' end end. (** Prove that [fib] satisfies the following equation. You will need this as a lemma in the next exercise. *) Lemma fib_eqn : forall n, n > 0 -> fib n + fib (pred n) = fib (1 + n). Proof. (* FILL IN HERE *) Admitted. (** [] *) (** **** Exercise: 4 stars, advanced, optional (fib) The following Imp program leaves the value of [fib n] in the variable [Y] when it terminates: X := 1; Y := 1; Z := 1; while X <> 1 + n do T := Z; Z := Z + Y; Y := T; X := 1 + X end Fill in the following definition of [dfib] and prove that it satisfies this specification: {{ True }} dfib {{ Y = fib n }} You will need many uses of [ap] in your assertions. If all goes well, your proof will be very brief. *) Definition T : string := "T". Definition dfib (n : nat) : decorated := <{ {{ True }} ->> {{ FILL_IN_HERE }} X := 1 {{ FILL_IN_HERE }} ; Y := 1 {{ FILL_IN_HERE }} ; Z := 1 {{ FILL_IN_HERE }} ; while X <> 1 + n do {{ FILL_IN_HERE }} ->> {{ FILL_IN_HERE }} T := Z {{ FILL_IN_HERE }}; Z := Z + Y {{ FILL_IN_HERE }}; Y := T {{ FILL_IN_HERE }}; X := 1 + X {{ FILL_IN_HERE }} end {{ FILL_IN_HERE }} ->> {{ Y = fib n }} }>. Theorem dfib_correct : forall n, outer_triple_valid (dfib n). (* FILL IN HERE *) Admitted. (** [] *) (** **** Exercise: 5 stars, advanced, optional (improve_dcom) The formal decorated programs defined in this section are intended to look as similar as possible to the informal ones defined earlier. If we drop this requirement, we can eliminate almost all annotations, just requiring final postconditions and loop invariants to be provided explicitly. Do this -- i.e., define a new version of dcom with as few annotations as possible and adapt the rest of the formal development leading up to the [verification_correct] theorem. *) (* FILL IN HERE [] *) (* 2022-10-06 21:00 *)