\documentclass[12pt,HW250,ifthen]{article} \newcommand{\into}{{\rightarrow}} \newcommand{\lf}{\left\lfloor} \newcommand{\rf}{\right\rfloor} \newcommand{\lc}{\left\lceil} \newcommand{\rc}{\right\rceil} \newcommand{\Ceil}[1]{\left\lceil {#1}\right\rceil} \newcommand{\ceil}[1]{\left\lceil {#1}\right\rceil} \newcommand{\floor}[1]{\left\lfloor{#1}\right\rfloor} \newcommand{\Z}{{\sf Z}} \newcommand{\N}{{\sf N}} \newcommand{\Q}{{\sf Q}} \newcommand{\R}{{\sf R}} \newcommand{\Rpos}{{\sf R}^+} \usepackage{amsmath} \begin{document} \centerline{Homework 7, Morally due FRI Apr 5, 5:00PM. DEAD CAT Monday Apr 8 5:00} (NOTE- Change of when its due is so that we can go over it in rec BEFORE the exam.) \centerline{\bf THE HW IS TWO PAGES LONG!!!!!!!!!!!!!} \newif{\ifshowsoln} \showsolntrue % comment out to NOT show solution inside \ifshowsoln and \fi blocks. \begin{enumerate} \item (20 points) \begin{enumerate} \item (10 points) WG, Jtwitty, and K are taking the class on a field trip to the Combinatorics Museum! There are 32 students in the class WG will drive 18 of them. Jtwitty will drive 7 of them. K will drive 7 of them. How many ways can the students choose which cars they want to be in? \item (15 points) Generalize the problem as follows. $A_1,\ldots,A_n$ are taking the class on a field trip! There are $S$ students in the class. $A_1$ will drive $a_1$ of them. $\vdots$ $A_n$ will drive $a_n$ of them. (Note that $a_1+\cdots+a_n=S$.) How many ways can the students choose which cars they want to be in? \end{enumerate} \item (25 points) Use a combinatorial argument (NOT algebraic, NOT by induction) to show that if $S=a+b+c$ then $$\frac{S!}{a! b! c!} = \frac{(S-1)!}{(a-1)! b! c!} + \frac{(S-1)!}{a! (b-1)! c!} + \frac{(S-1)!}{a! b! (c-1)!}$$ \centerline{\bf GOTO NEXT PAGE} \newpage \item (25 points) Fill in the blanks in the following statement. Describe your reasoning. BLANK will be a function of $k,n$. {\it If $A\subseteq \{1,\ldots,n\}$ and $|A|=k$ then at least BLANK subsets of $A$ have the same SUM.} \item (25 points) Show that no matter how you 3-color the $4\times 19$ grid there will be a monochromatic rectangle. \end{enumerate} \end{document}